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Rank of Matrix and Pivots | Linear Algebra

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Rank of Matrix and Pivots | Linear Algebra

This lesson is a sample from The Ultimate Crash Course for PLEM Majors series.

Study linear algebra, differential equations, calculus, physics, and engineering mathematics with over 1,000 ad-free STEM lessons.

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Rank of matrix and pivots

\begin{bmatrix}1&1\end{bmatrix},\qquad rank(A_1)=1

\begin{bmatrix}1\\1\end{bmatrix},\qquad rank(A_2)=1

\begin{bmatrix}1&1&1\end{bmatrix},\qquad rank(A_3)=1

\begin{bmatrix}1\\1\\1\end{bmatrix},\qquad rank(A_4)=1

\begin{bmatrix}1&0\\0&1\end{bmatrix},\qquad rank(A_5)=2

\begin{bmatrix}1&0&0\\0&1&1\end{bmatrix},\qquad rank(A_6)=2

\begin{bmatrix}1&0\\0&0\\0&1\end{bmatrix},\qquad rank(A_7)=2

\begin{bmatrix}1&1\end{bmatrix},\qquad rank(A_8)=1

\begin{bmatrix}1\\0\end{bmatrix},\qquad rank(A_9)=1

\begin{bmatrix}1&1&1\end{bmatrix},\qquad rank(A_{10})=1

\begin{bmatrix}1\\0\\0\end{bmatrix},\qquad rank(A_{11})=1

\begin{bmatrix}1&1&1\\1&1&1\\1&1&1\end{bmatrix},\qquad rank(A_{12})=1

\begin{bmatrix}1&1&1\\1&1&-1\\1&1&1\end{bmatrix},\qquad rank(A_{13})=2

\begin{bmatrix}1&1&1\\0&1&1\\0&0&1\end{bmatrix},\qquad rank(A_{14})=3

Note: max rank is the smaller dimension of n\times m e.g. 3\times7 means that 3 is the highest possible rank. It goes with the transpose as well i.e. 7\times3 still has a highest rank of 3.

A= \begin{bmatrix} 1&2&1&1&1&1\\ -1&-2&1&1&1&1 \end{bmatrix} \qquad R1+R2\Leftarrow R2

\sim \begin{bmatrix} 1&2&1&1&1&1\\ 0&0&2&2&2&2 \end{bmatrix} \Rightarrow rank(A)=2

Ax=b \Rightarrow \left[ \begin{array}{ccc|c} 3&2&3&1\\ 1&3&3&3\\ 3&2&1&1 \end{array} \right]

\sim \left[ \begin{array}{ccc|c} 1&0&0&-\frac37\\ 0&1&0&\frac87\\ 0&0&1&0 \end{array} \right], \qquad rank(A)=3

i.e. A= full rank

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